4.9t^2+506.11t=545

Solution for 4.9t^2+506.11t=545 equation:

4.9t^2+506.11t=545

We move all terms to the left:

4.9t^2+506.11t-(545)=0

a = 4.9; b = 506.11; c = -545;
Δ = b2-4ac
Δ = 506.112-4·4.9·(-545)
Δ = 266829.3321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(506.11)-\sqrt{266829.3321}}{2*4.9}=\frac{-506.11-\sqrt{266829.3321}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(506.11)+\sqrt{266829.3321}}{2*4.9}=\frac{-506.11+\sqrt{266829.3321}}{9.8}
$